This preview shows page 1. Sign up to view the full content.
Unformatted text preview: the mass were concentrated at the center of mass. Consequently, (2.2.10) and (2.2.11) * To illustrate that the internal forces integrate to zero consider an ensemble of N interacting particles. An internal force is applied between two particles: fij = fii, where ft is the force on the ith particle due to the source connected between the ith and jth particles. The total internal force on the ith particle is N fi= fij' 5=1 ii The total internal force on the ensemble is N NN i=1 i=1 1=1 Because f,, = fi, we conclude that each term in this summation is canceled by an equal and opposite term and the net internal force is zero. If we let N oo, the nature of the result is unchanged; thus we conclude that the integral of internal forces over the volume of a rigid body must be zero. APDF Split DEMO : Purchase from www.APDF.com to remove the watermark...
View
Full
Document
This note was uploaded on 02/10/2012 for the course MECE 4371 taught by Professor Liu during the Fall '11 term at University of Houston.
 Fall '11
 Liu

Click to edit the document details