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Unformatted text preview: the mass were concentrated at the center of mass. Consequently, (2.2.10) and (2.2.11) * To illustrate that the internal forces integrate to zero consider an ensemble of N inter-acting particles. An internal force is applied between two particles: fij = -fii, where ft is the force on the ith particle due to the source connected between the ith and jth particles. The total internal force on the ith particle is N fi= fij' 5=1 i-i The total internal force on the ensemble is N NN i=1 i=1 1=1 Because f,, = --fi, we conclude that each term in this summation is canceled by an equal and opposite term and the net internal force is zero. If we let N -oo, the nature of the result is unchanged; thus we conclude that the integral of internal forces over the volume of a rigid body must be zero. A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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This note was uploaded on 02/10/2012 for the course MECE 4371 taught by Professor Liu during the Fall '11 term at University of Houston.
- Fall '11