This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: D    D    CTD c  = 5 . Finally  C c D c T c  =  S    T    CDT c    CD c T c    DC c T c  = 9 . (b) Due to part (a) the answer is ± 9 2 ² ± 100 2 ² = 9 × 8 100 × 99 . (4) (a) We have 12 balls 9 of which are non green. If 2 green balls are chosen then 4 non green balls are chosen. Therefore the answer is ± 3 2 ²± 9 4 ² ± 12 6 ² . (b) Let R,B,G and W denote the event that red (respectively blue, green or white) is complete. Similarly to part (a) we have P ( R ) = ± 9 3 ² ± 12 6 ² , P ( RB ) = 1 ± 12 6 ² , P ( RBG ) = 0 1 2 and similar formulas for other colors. Thus the answer is ± 4 1 ² ± 9 3 ² ± 12 6 ²± 4 2 ² 1 ± 12 6 ² ....
View
Full
Document
This note was uploaded on 02/09/2012 for the course STAT 410 taught by Professor Staff during the Spring '08 term at Maryland.
 Spring '08
 staff

Click to edit the document details