Unformatted text preview: 2 too small, probably because of the slope of the table or friction or whatever. This is the kind of thing you talked about in your answers to questions #13 and #14. Your actual intercept will be different. It may be positive. That means your acceleration values are too big. If you were to go back to your data tables and add in the 0.05 m/s 2 that is missing, you would have the “ perfect ” acceleration values that you would get with a perfect table, no friction, etc. If you graph these “ perfect ” acceleration values vs. the total mass, your best fit curve would have an exponent closer to -1. The coefficient of the function would be much closer to 2000. Your answers to #17 and #18 would be much closer together. Your answer to #19 would be easier to figure out....
View Full Document
This note was uploaded on 02/10/2012 for the course PHYS 123 taught by Professor Phys123 during the Spring '10 term at Buena Vista.
- Spring '10