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Unformatted text preview: ECE 4991 Electrical and Electronic ECE 4991 Electrical and Electronic Circuits Circuits Chapter 3 Chapter 3 2 Where are we? Where are we? Chapter 2  The basic concepts and practice at analyzing simple electric circuits with sources and resistors Chapter 3 More harder networks to analyze and the notion of equivalent circuits Chapter 4 Capacitors and inductors added to the mix Chapter 5 Analyzing transient situations in complex passive networks Chapter 8 New subject the wonders of operational amplifiers as system elements Chapter 9 Introduction to semiconductors the basics and diodes more network analysis Chapter 10 Bipolar junction transistors and how they work now you can build your own op amp 3 Whats Important in Whats Important in Chapter 3 Chapter 3 1. Definitions 2. Nodal Analysis 3. Mesh Analysis 4. The Principle of Superposition 5. Thevenin and Norton Equivalent Circuits 6. Condition for Maximum Power Transfer 4 1. Definitions 1. Definitions Node voltages Branch currents Ground KCL Nodal Analysis Mesh currents KVL Mesh Analysis Principle of Superposition Equivalent circuit Thevenin theorem Norton theorem Oneport networks Source loading 5 2. Nodal Analysis 2. Nodal Analysis Used to analyze circuits Solve for currents, voltages, power, etc., throughout circuits Applies KCL to nodes Often used in concert with Ohms Law 6 Node Method Node Method Find nodes Identify ground node Label branch currents &amp; node voltages Node voltages, if not defined by a voltage source, are independent variables Write KCL for nodes Solve for unknowns 7 i S R 1 R 2 R 3 Working with Nodal Working with Nodal Analysis Analysis 1. Reference Node Selection (usually Ground) 2. Define remaining n1 node voltages. 3. Apply KCL to obtain Nodal Expressions for node a and b respectively: i s i 1 i 2 = 0 i 2 i 3 = 0 i S Node c Node a Node b i 1 i 2 i 3 8 i S R 1 R 2 R 3 Working with Nodal Working with Nodal Analysis (cont.) Analysis (cont.) 1. Apply Node Voltage Method 1 1 R v v i c a = i S Node c Node a Node b i 1 i 2 i 3 2 2 R v v i b a = 3 3 R v v i c b = 9 Working with Nodal Working with Nodal Analysis (cont.) Analysis (cont.) Substitution step leads to: Or equivalently to: 3 2 2 1 = = R v R v v R v v R v i b b a b a a s 1 1 1 1 1 1 3 2 2 2 2 1 = + +  =  + + b a s b a v R R v R i v R v R R 10 Example 3.2 Example 3.2 Solving for all unknown currents and voltages in the circuit of Figure 3.5 R 1 =1k, R 2 =2k, R 3 =10k, R 4 =2k, I 1 =10mA, I 2 =50mA I 1 R 1 R 2 R 4 I 2 R 3 Node 1 Node 2 11 Example 3.2 (cont.) Example 3.2 (cont.) Applying KCL at nodes 1 &amp; 2: After rewriting: 2 4 2 3 2 1 2 2 1 3 2 1 2 2 1 1 1 1 =...
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This note was uploaded on 02/11/2012 for the course ECE 4991 taught by Professor Crandel during the Fall '07 term at FIT.
 Fall '07
 CRANDEL

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