centrif - R2 R3 centrifugal increasing gravity increasing F...

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gravitation g R1 oblate spheroid The reduction in gravitation (apparent gravity) leads to an equatorward component of gravity and hence a shearing stress which deforms the earth. Hence, the equator is uphill! Why doesn’t the object roll toward the pole?
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Unformatted text preview: R2 R3 centrifugal increasing gravity increasing F gravitation /m = -GM r r2 THIS IS ONE OF THE APPARENT ACCELERATIONS! g = F gravitation /m + F centrifugal /m F centrifugal /m = 2 rR r R CENTRIFUGAL g*...
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This note was uploaded on 02/11/2012 for the course MET 4305 taught by Professor Lazarus during the Fall '09 term at FIT.

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