3241.CQ8 - inviscid momentum equation. Perhaps the quickest...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
MAE 3241: Aerodynamics and Flight Mechanics Name: _________________ Concept Quiz #8 We have spent a good amount of time studying the following flow field in detail: ( 29 2 2 y x a u - = axy v 2 - = 0 = w We have shown that the velocity field is steady, incompressible, and irrotational. If we now add the assumption that the flow is also inviscid, as well as neglecting any external or body forces, the velocity field is subject to Newton’s second law through the momentum equation, given in vector form below: p Dt V D - = ρ 1 e 1 For this concept quiz, determine if the given velocity field given is a solution to the
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: inviscid momentum equation. Perhaps the quickest and easiest way to do this is: 1) Evaluate the momentum equation in the x- and y-directions 2) Compare the second-order mixed partial derivates of the pressure: y x p ∂ ∂ ∂ 2 . If this term is identical in both directions (x and y), then the velocity field is a solution to Equation 1. If the mixed derivatives are not identical, the flow field given above is not a solution of Equation 1. Also note that: x y p y x p ∂ ∂ ∂ = ∂ ∂ ∂ 2 2 ....
View Full Document

This note was uploaded on 02/11/2012 for the course MAE 3241 taught by Professor Staff during the Spring '11 term at FIT.

Ask a homework question - tutors are online