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Unformatted text preview: inviscid momentum equation. Perhaps the quickest and easiest way to do this is: 1) Evaluate the momentum equation in the x and ydirections 2) Compare the secondorder mixed partial derivates of the pressure: y x p ∂ ∂ ∂ 2 . If this term is identical in both directions (x and y), then the velocity field is a solution to Equation 1. If the mixed derivatives are not identical, the flow field given above is not a solution of Equation 1. Also note that: x y p y x p ∂ ∂ ∂ = ∂ ∂ ∂ 2 2 ....
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This note was uploaded on 02/11/2012 for the course MAE 3241 taught by Professor Staff during the Spring '11 term at FIT.
 Spring '11
 Staff

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