211chp4 - Chapter 4 Homework Solutions 9/21/10 16. a) Mg2+,...

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Chapter 4 Homework Solutions 9/21/10 16. a) Mg 2+ , I - b) Al 3+ , NO 3 - c) H + , ClO 4 - d) Na + , CH 3 CO 2 - 19. soluble: NiCl 2 , Cs 3 PO 4 insoluble: Ag 2 S, SrCO 3 , PbSO 4 22. a) Ni(NO 3 ) 2 (aq) + 2 NaOH (aq) Ni(OH) 2 (s) + 2 NaNO 3 (aq) b) No precipitate or reaction. c) Na 2 S (aq) + Cu[CH 3 CO 2 ] 2 (aq) CuS (s) + 2 Na[CH 3 CO 2 ] (aq) 30. The Ba(OH) 2 solution is most basic. Although more concentrated, ammonia is a weak base. Barium hydroxide is more basic than potassium hydroxide because it has 2 hydroxide ions per metal ion rather than 1. 35. a) acid, mixture b) none of the above, molecules c) salt, ions d) base, ions 38. Strong electrolytes: HClO 4 , HNO 3 , NH 4 Cl, CoSO 4 Nonelectrolytes: sucrose, acetone Weak electrolytes: none 40. a) CH 3 COOH (aq) + KOH (aq) K[CH 3 COO] (aq) + H 2 O ( ) CH 3 COOH (aq) + OH - (aq) CH 3 COO - (aq) + H 2 O ( ) b) Cr(OH) 3 (s) + 3 HNO 3 (aq) 3 H 2 O ( ) + Cr(NO 3 ) 3 (aq) Cr(OH) 3 (s) + 3 H + 3 H 2 O ( ) + Cr 3+ (aq) c) Ca(OH) 2 (aq) + 2 HClO (aq) Ca(ClO) 2 (aq) + 2 H 2 O ( ) HClO (aq) + OH - (aq) ClO - (aq) + H 2 O ( ) 46. No. Oxidation occurs when an electron is removed from a species. That electron must go somewhere. The species that receives the electron is reduced, so the two processes must occur together. 50. a) +4 b) +2 c) +3 d) -2 e) +3 f) +6 52. a) acid-base b) redox: Iron is reduced and carbon is oxidized. c) precipitation d) redox: Zinc is oxidized and nitrate ion is reduced. 54. a) Ni (s) + 2 HCl (aq) NiCl 2 (aq) + H 2 (g) Ni (s) + 2 H + (aq) Ni 2+ (aq) + H 2 (g) b) H 2 SO 4 (aq) + Fe (s) FeSO 4 (aq) + H 2 (g) Fe (s) + 2H + (aq) Fe 2+ (aq) + H 2 (g) c) 2 HBr (aq) + Mg (s) MgBr 2 (aq) + H 2 (g) Mg (s) + 2 H + (aq) Mg 2+ (aq) + H 2 (g) d) Zn (s) + 2 HC 2 H 3 O 2 (aq) Zn(C 2 H 3 O 2 ) 2 (aq) + H 2 (g)
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Same as the molecular equation since acetic acid is a weak acid. 58. a) Since Br 2 oxidizes I - to I 2 , bromine is more active than iodine. Likewise, since Cl 2 oxidizes Br - to Br 2 , chlorine is more active than bromine. The activity series goes Cl 2 > Br 2 > I 2 . b) Moving down Group VII, halogens become less active. c) Cl 2 /KI: I - will be oxidized to I 2 Br 2 /LiCl: no reaction will occur 62. a) [Na 2 SO 4 ] =   soln Na2SO4 Na2SO4 Na2SO4 L 0.850 1 g 142.04 mol 1 g 750 0 . = 6.21 x 10 -3 M b) mol KMnO4 = (0. 250 L) soln KMnO4 L mol 0.0475 = 0.0119 mol KMnO4
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211chp4 - Chapter 4 Homework Solutions 9/21/10 16. a) Mg2+,...

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