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EEE463_Homework6_Solution_F07

# EEE463_Homework6_Solution_F07 - #Naﬁana(”Brand i E i 1...

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Unformatted text preview: #Naﬁana/ (”Brand i E i 1 E , , __, u M _ ,4 L 3-1 Show that the efﬁciency of an ideal Brayton cycle at the optimum pressure ratio is a function of minimum and maximum temperatures only, and independent of the working ﬂuid. Eﬁutrf—{on (5"[69 gives 4‘17: Whit/7.57 a! 441.9 [Jeo/ Bray/Ur; C‘yc/ca ﬂﬁ‘ :1—n—(éjm (aw/c9 (incl 59. [BE—l6”) prowder 41135 op¥imumlore\$~5ure rmL/o Ow (:2 )k/JW D (3-H) wkeo’e 77 4nd 7— 009 #4,? mun/Hum and de/mum +emfdera+ufes/ ﬂex/06d? v’é/y. Squéy/vvzuvL/g (8 [(74) mfc (8MIO> lyre/J5 ﬂ+a= kZéj—z‘; ,ly/Mk ypezJ/f " 7 a i e =Ei -4/2 E 13)”? L\ 73 '> T, ”NH” 8-3 A gas turbine cycle operates with air only with a constant speciﬁc heat of 0.24 Btu/lb... - ”R. The inlet air is at 14.696 psia and 60°F. The maximum cycle temperature is 1800°F. The compressor and turbine have thesame’pressune ratio of 8 and polytnopic efﬁciencies of 0.85. A regenerator with 75 percent effectiveness is considered. Calculate (a) all temperatures around the cycle, in degrees Fahrenheit, (b) the efﬁciency of the cycle, in percent, (6) the heat added, in Btus' per hour," to produce l'O-MW power. (d) the efﬁciency of the cycle if no regenerator is used, (e) the efﬁciency of a comparable ideal cycle with a perfect regenerator. CF : 0.94 Bil-u/llém’gfﬂf SQUAHE SQUARE SQUARE SQUARE SQUARE mmmmmm PP = 8 é§= 0.75 520%: /’?C = 0,85 = {2,7, F,‘¢5+J 43/10; 'Hie [clever] +eM/geravl‘ur‘w 97F atria, ‘. , Sr‘ncéa [grab/em “La-\$33 carts-FanvL a; a'p Do 2‘74, wig; w?” use ass-arms) cons-1%»! I? 3 [.4130 scream 72%é»8“l . _. i _ T 18\$“ 4606/? c E?" (843' 713- 273W = ”("27'““7“-+-« W = Weary? ”88 F @Py”/‘ =(éo + 4503(8‘E'WW = 94:2 922 staff: 3 7S EYEvEASE’” TS EV'E‘EREE“ h s 3: 5% § ‘2‘ ‘2‘ 7716 compressar zinc; altar/area. ewe/Male: clvonﬁé» 7; and 7‘; e .. ——= 12;}! %> T- _ , 325‘74 E‘f'( I53 ‘ 0c 7 7.2-71» .2 ‘ i1 72 O _ ‘QF ‘3 _ £0 F" 4-8-2 63 55 7;-T4 E? (8“185: HT : Trim :5? 7—3“ = T3'4T(7}* 7:93) = mom:— (o.as>(7ew-7aaea5 -—-. 939.an 77mm +Lg regenera-i‘fon cor-4e: [xi-Fa play ‘ _ T —T 59, (8'2”?)7 6‘6 "ﬂ =9 T}, :1: 21-6,? (TV-"'72) = 556°F+(O.7SX939_8 *gSG‘YJ = 8%5’.8F°F KaSﬂmpena-Fure: abound! ‘qu? eye/a are Coanesgon (Ii/ey‘ 3 7-, =5 60‘7". Compressor“ Qu'Hg-F delmf = 715 =' 474823: Comprgss'cr" Ou‘He'I (Qc‘izum/ 7 7—3 7: 556‘; = heﬁcaereile» m Am“ Rcaemra‘i‘or ou‘iL/e'i' : 73/ 7" 89-9-5: Turbine [ft/£1“ '. T3 = leeoﬂp Tu’éac'ne mud Cféataé) 27’43 : 7g8°r= Tabla/lee Gui-[:4 (ac-inc. f\ 3 T9; = C7400): ...
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EEE463_Homework6_Solution_F07 - #Naﬁana(”Brand i E i 1...

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