hw5_sol_printable

hw5_sol_printable - HWS A l(iWe power plum with a beam rule...

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Unformatted text preview: HWS A l-(iWe power plum with a beam rule of 3300 BuflWh Operates at full powar for a period of 1 day. Find: (:1) the mass uf'cml, in tons per day, and {b} the volume ofoi], in barrels per day, muted for opermiun a}: fil“ power. Assume that the energy cement (heating value) nf‘the coal is 2?,800 kakg, and that ofthe oil is 14 I .000 Hfgal. Then: an: 42 gallons ofuil per barrel. _ Pa. 2% * fl”, = a (w) =floééwg)(%%§fi = 8.8x.ch 9 Batu/A,» __ F’fi 3.3::093m A» {gr/x 500%} ,4 Ce) ana-f " u“ = (127;: am er/kjs {3W2 mu/ag _. in 2a; 3 Z 5» a 6’0 wager} _. p-ifi _ 3.33101; git Jl'h- fiJ’ZgE-f .2?- fir 65) Li” " yu ‘ bar-{iaoa kaygaitjs-fiwz HT‘q/firi Ar Xgay D = 55mm“ 3aI/Qay)(%éfififi ={ 3'? .930 éorrajsyd’fl/vi 2. A fuel is hmned in 20% excess air. Detennine the percent by volume of each constituent in the flue gas. The file]. has the follmving elemental analysis in weight percent {WM}: [12 pts] C 32.1 win 3 0.2 win H2 17".? win A Puslr .‘f‘JCIS- 4%. siren-1:14:91! amfyses 5 Wga C. 82.1 S 0.2 Hz .17. '7 :4? HM: is burned. in 297:3 19:?ch 95"; Aggro-Hide 1%: perms-~24- é); vofume up each cans-Hep”? m 415;. Plus. 395‘. E t 2-4. can? e (22* -i-’ + 2......) (a. + m m) —* A'I'I Zia-F Zi ZitFCSoA) ‘4- + T + Z.” a M 0.9:.” “(has Carhan' 24= = 0.0684 “A: Hyatt-nag»: 3;“: 07177 matte £9.56 sum», : 2m = 33737: = QDOOOéS Mate A» 1 2,: + 4-24" +2.}: -_— aoee4+ $223K +£3.000C363 = 0-i127mfe “Jug-.1; Oxyaerr (0Q : (34m) ('0. a) = (o.1127){o.:) = o.o:25+ m}: N.‘+ma“ (N35 : (A;p)(3.7é)@.=):(a 11:: gamma) = 0.5085 and; f CO; : 2' = (3.0634— (mulle- a! 2'1: . 24.10 = *E’= M a =Qoaas MEL- SOJ : :2th = QDGOUQE? flflfc. 5:11:49 fine moire a‘pdry Fain-I no: eceufics ma unjuflg", 4-4.";- +i5w medic gag-Fran J's Eeul'mlren‘F '1':- 443 waft—wins pffi'fi'ffififl- Tat-ti Naif: = 0.02954 + 0.5935 r float-14+ 0.0335 + 0.000053 = 0:- (Wu-{ES a. 22:1 ' ' ' £1312 : c.9439. = 0.5337 " 9.7% CD: a. seas i; N; = "mg = 0.739 73.? 94:, IV; aces-F- : (20:1 "521m" = 633.09 ‘1' 9‘3 "/0 C04 H3o= Betas—$3; = 0.1.29 1.2.914, H.0- 50...= W: @0001 0.01 ‘34, SO, I' Jen-H 5;, 3. A steam plant produces 500 We with a thermal efl'ieiency of 35%. The coal used has a heating value of 25,000 klfkg and a sulfin' content of 2.3%. The stack gas scrubber remcrves 95% of the SCI; produced and discharges a slurry of CaSD4 which is 45 weight percent CaSO4_ What is the annual volume of slutty pi‘udueed if the plant operates at 75% capacity factor? The density of calcium sulfate [CaSO4) is 2.96 gr'cms. [10 pts] MHW’ Fran-F 771an {Psi-in.“ ‘ pfll = E W: .14'351 MW ‘3. Hgfinfich-EL 14:!" l regur'rcmre-d'l': 91L power“ flfiéflfickT/flgéW-uc = 5:21 tea/LC: 905,7 5' leg/Jin- Ié- .I"- fly - Cfiol Rainfall}? use-cl = 6305!, 705 éé‘f’fi : = 1.35 an: ID? Lia/yr" 1:. _\ Sulfur- laumeal “(Wesmmqéig -= 31.1,: D‘% Mensa, = 45* 33*(fifl4) = 136 Jag/mg}? :qus .341“ {7950+ = (sine? if) W) (63.95) 4 I —- 125.:ch s5 CaSlefya-w Etc-3:51., = 9' J ERIE-alum lair-flail:- ! Law iiémroek r520 '\ r 3 ivai. CGSOq. = 5 -WW—%WAfi/—kjflfi—‘fimm '= 42,5?0 nae/y» I 5%5 ling :- Mflij INF #4:} =(_+SA§§D‘_)(:£REK Ilrcl' /yr> = 15+ x mtg} Him/w J K ‘éfi iffi tr“ 5 i m U9}: ill-{23: 5.?ij c} (in: XME-fl'r 3 : 15+,aco (ME/V. Tam Vanna...— : vat $301+ Vat His 3 3 = (42}5?of’:) + (rs‘fi HIDE? t 1.97); {C‘s ms/Yr' #12. _-— -' '--. ._- 4- Calcu'lalg (a) lb: 130er of the wind. [bl Eh: thmrclical maximum attainabb: fill-him power. [5) I masmably attainable mrbinc power. all in horsepower and mamas, (d) m; toque. m1 (9} the am; --- 14-] A 27 mifll wind 31 [4.65 psi: and “MT calm a turbine whael that has a illilflfl-tlI muss-Sectional Ina. ' llmlsl.tnpoundfome.ifthcturhilluiueimcs£30flmin. l L “9‘” 32.2 = 71% pm =%{?7.s-é kw) =(5_7.3_I:_w:f(x.3w;{’fi) =[7753E] c) A55um:'n§ 11:40:29 (as in Paraffc’ fixqm’ol‘E’ {LIL-1') mac—h ET [Hf—30> __ P = 2’? PM! = (0.4)(4755 kw) =Z:3_9.D_17E (L34! £35 ___ Wm: #:1191124 U3in5 E19 54’31) I E - 551:; '. _r'-——-'—”"" a T: 2w "' Eiixs'ogfiw—gfig =L‘L'féilirfl7 __—.__—_— —__ _,—-__._._._.._.—_._.____.—._ _ ‘ = fiéIS 1'53: ; Tm“ 2w» “ (zwjfioa'rf figfi) » 1*” I TAB-r JFFDLJFM I": Fin-4:142? 41: IMAM-1am MIdMfiIMflWMflgIM-hpfiodhwhflflnmm Whlfinflmwhfl’lfimwlwnfifl] - v_m(m4].manmhmmv_ - Wm.mmmhn.mm.mmmmmmmmmwm 23m.hfmt-pmnd_fmeuflmm.udw}ficwindmlmy “magnum _ fl ‘ \d, “I p = 21114;} 6+® (g) g- mcmmum Wm Pom/ra- LI mag :73: 171:. maximum Enurgy r]: H: {mi-5w! cv'er 4w: z 1+ :1 me=meadt : 35 L—D what-35a c 375:; = .2 w- 5'0“ 2+ , .11.".73a a Vms 5:313 4‘51 From .4 44-514? a‘p inJ-aljrfl-f-f-i 53:}! 362K) 44% = %q‘(_ can: (6:) 5.1-: “(a-r) + 2] u cos-3(ox) 5.91473) a _ a. II (5' 2 Em = 217* 5‘0: Vflljfcosa ‘3‘? _ an: If 7 + 275:: 3 .14 f3? r a 3 . 5 0.076 too-r1! I {as - H | 2-7 ‘hl‘zxifl Mar/IQ»: £245! _, 3 +1 I " g cagjs‘fi‘fi- Efifij) .._ E I r‘ .r‘ = (3.2‘l‘x1’0q fag—“PO §F%+IY‘[%‘57§ = @fimfi MW I = DEE—N'CI/ '16,) The, 51:15.}: efuc‘it;an +0 41:53 4-5;: aver-n55:- val’ufi f5 m— E 2+ - E | Eva ‘ t Eafiosmlfi, , i ll : Ema? gees-$3] I EM #2- .averq e value :15. r101]- wfim-f'r Hive Froéfem I filo-GS aséed an". I ...
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This note was uploaded on 02/11/2012 for the course EEE 463 taught by Professor Holbert during the Spring '08 term at ASU.

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