problem03_33

University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.33: a) From Eq. (3.31), 2 2 m/s 3.50 m) 0 . 15 /( m/s) 00 . 7 ( = = a . The acceleration at the bottom of the circle is toward the center, up. b) 2 m/s 50 . 3 = a , the same as part (a), but is directed
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Unformatted text preview: down , and still towards the center. c) From Eq. (3.29), s 12.6 m/s) m)/(7.00 . 15 ( 2 / 2 = = = π v R T ....
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This document was uploaded on 02/04/2008.

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