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Unformatted text preview: Stat 511 Homework 8 Spring 2011 Due: 11am, Monday Mar 21 1. The data in range.txt come from a field study of plant response to fertilization. There are five treatments (a control and four different fertilization regimes) randomly assigned to plots arranged into blocks. The response is the average PO4 concentration in plant leaves. (a) Assume blocks are a fixed effect and analyze the data. Report: The F statistic and pvalue for the test of no differences among fertilizer treatments The estimated diffence between between the 100lb.N treatment and the 100lbNP treat ments and its se. The mean for the No fertilizer (No.fert) treatment (averaged over blocks) and its se. (b) Assume blocks are a random effect and analyze the data. Report: The F statistic and pvalue for the test of no differences among fertilizer treatments The estimated diffence between between the 100lb.N treatment and the 100lbNP treat ments and its se. The mean for the No fertilizer (No.fert) treatment (averaged over blocks) and its se. (c) Using the default parameterization, R reports an estimated intercept of 4.2520 when using a fixed block analysis and 6.5800 when using a random block analysis. Explain why these numbers are different and how you can extract 6.5800 from the estimateswhy these numbers are different and how you can extract 6....
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This note was uploaded on 02/11/2012 for the course STAT 511 taught by Professor Staff during the Spring '08 term at Iowa State.
 Spring '08
 Staff

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