HW01_Solutions - HOMEWORK 1: ELECTRIC CHARGE 21.17....

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21-1 H OMEWORK 1: E LECTRIC C HARGE 21.17. IDENTIFY and SET UP: Apply Coulomb’s law to calculate the force exerted by 2 q and 3 q on 1 . q Add these forces as vectors to get the net force. The target variable is the x -coordinate of 3 . q EXECUTE: 2 F is in the x -direction. 12 22 2 12 3.37 N, so 3.37 N x qq F k F r   23 and 7.00 N x x x x F F F F   32 7.00 N 3.37 N 10.37 N x x x F F F     For 3 x F to be negative, 3 q must be on the x -axis. 1 3 1 3 3 2 3 , so 0.144 m, so 0.144 m q q k q q F k x x xF   EVALUATE: 2 q attracts 1 q in the x -direction so 3 q must attract 1 q in the x -direction, and 3 q is at negative x. 21.24. IDENTIFY: Apply 2 k qq F r to find the force of each charge on q . The net force is the vector sum of the individual forces. SET UP: Let 1 2.50 C q  and 2 3.50 C q  . The charge q must be to the left of 1 q or to the right of 2 q in order for the two forces to be in opposite directions. But for the two forces to have equal magnitudes,
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This note was uploaded on 02/11/2012 for the course PHYSICS 222 taught by Professor Ogilvie during the Fall '05 term at Iowa State.

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HW01_Solutions - HOMEWORK 1: ELECTRIC CHARGE 21.17....

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