HW07_Solutions

HW07_Solutions - HOMEWORK 7 SOLUTIONS Q25.5 ANSWER no...

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HOMEWORK 7: SOLUTIONS Q25.5: ANSWER: no current is induced, because magnetic flux through the ring is zero. 29.1. I DENTIFY : Altering the orientation of a coil relative to a magnetic field changes the magnetic flux through the coil. This change then induces an emf in the coil. S ET U P : The flux through a coil of N turns is Φ = NBA cos φ , and by Faraday’s law the magnitude of the induced emf is = d Φ /dt . E XECUTE : (a) ∆Φ = NBA = (50)(1.20 T)(0.250 m)(0.300 m) = 4.50 Wb (b) = d Φ /dt = (4.50 Wb)/(0.222 s) = 20.3 V 29.5. I DENTIFY : Apply Faraday’s law. S ET U P : Let + z be the positive direction for. Therefore, the initial flux is positive and the final flux is zero. E XECUTE : (a) and (b) Since is positive and is toward us, the induced current is counterclockwise. E VALUATE : The shorter the removal time, the larger the average induced emf. 29.7. I DENTIFY : Calculate the flux through the loop and apply Faraday’s law. S

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HW07_Solutions - HOMEWORK 7 SOLUTIONS Q25.5 ANSWER no...

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