HW09_Solutions - HOMEWORK 9 SOLUTIONS Q30.6 ANSWER...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
HOMEWORK 9: SOLUTIONS Q30.6: ANSWER: self-inductance is proportional to total flux. If the radius is doubled, flux increases 4 – fold, so self-inductance increases accordingly. . 30.02. I DENTIFY : and , where is the flux through one turn of the second coil. S ET U P : M is the same whether we consider an emf induced in coil 1 or in coil 2. E XECUTE : (a) (b) (c) E VALUATE : We can express M either in terms of the total flux through one coil produced by a current in the other coil, or in terms of the emf induced in one coil by a changing current in the other coil. 30.11. I DENTIFY and S ET U P : Use Eq.(30.6) to relate L to the flux through each turn of the solenoid. Use Eq.(28.23) for the magnetic field through the solenoid. E XECUTE : If the magnetic field is uniform inside the solenoid From Eq.(28.23), Then E VALUATE : Our result is the same as L for a torodial solenoid calculated in Example 30.3, except that the average circumference of the toroid is replaced by the length l of the straight solenoid. 30.21.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 02/11/2012 for the course PHYSICS 222 taught by Professor Ogilvie during the Fall '05 term at Iowa State.

Page1 / 2

HW09_Solutions - HOMEWORK 9 SOLUTIONS Q30.6 ANSWER...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online