HW09_Solutions

# HW09_Solutions - HOMEWORK 9 SOLUTIONS Q30.6 ANSWER...

This preview shows pages 1–2. Sign up to view the full content.

HOMEWORK 9: SOLUTIONS Q30.6: ANSWER: self-inductance is proportional to total flux. If the radius is doubled, flux increases 4 – fold, so self-inductance increases accordingly. . 30.02. I DENTIFY : and , where is the flux through one turn of the second coil. S ET U P : M is the same whether we consider an emf induced in coil 1 or in coil 2. E XECUTE : (a) (b) (c) E VALUATE : We can express M either in terms of the total flux through one coil produced by a current in the other coil, or in terms of the emf induced in one coil by a changing current in the other coil. 30.11. I DENTIFY and S ET U P : Use Eq.(30.6) to relate L to the flux through each turn of the solenoid. Use Eq.(28.23) for the magnetic field through the solenoid. E XECUTE : If the magnetic field is uniform inside the solenoid From Eq.(28.23), Then E VALUATE : Our result is the same as L for a torodial solenoid calculated in Example 30.3, except that the average circumference of the toroid is replaced by the length l of the straight solenoid. 30.21.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 02/11/2012 for the course PHYSICS 222 taught by Professor Ogilvie during the Fall '05 term at Iowa State.

### Page1 / 2

HW09_Solutions - HOMEWORK 9 SOLUTIONS Q30.6 ANSWER...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online