HW15_Solutions - HOMEWORK 15: SOLUTIONS . Q40.5 ANSWER:...

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HOMEWORK 15: SOLUTIONS . Q40.5 ANSWER: According to Fig.40.5, | Ψ | 2 is symmetric with respect to L/2, so the probability to find the particle in right half of the box is ½ for any n. 40.2. 40.21. and (a) (b) 40.34. I DENTIFY : If the given wave function is a solution to the Schrödinger equation, we will get an identity when we substitute that wave function into the Schrödinger equation. S ET U P : The given function is and the one-dimensional Schrödinger equation is E XECUTE : Start with the given function and take the indicated derivatives: Substituting these results into the one-dimensional Schrödinger equation gives E VALUATE : is a solution to the one-dimensional Schrödinger equation if or (Since was given, k is the square root of a positive quantity.) In terms of the particle’s momentum p : and in terms of the particle’s de Broglie wavelength 41.8.(a) As in Example 41.3, the probability is . (b)
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HW15_Solutions - HOMEWORK 15: SOLUTIONS . Q40.5 ANSWER:...

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