hw5ans - Statistics 500 Fall 2009 Solutions to Homework 5 1...

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Statistics 500 – Fall 2009 Solutions to Homework 5 1 1. Diagnostics for the diet and longevity study (a) Independence: look at the study design. Treatments were randomly assigned to individual mice; longevity was measured on individual mice. So, e.u. = mouse is the same as the o.u. = mouse. No obvious problem with lack of independence. (b) Equal variances: a variety of diagnostic methods (e.g. residual vs predicted value plot, box plots of the observations in each group, or calculation of the within group s.d.) or tests (Levene’s test) are acceptable. All groups have similar variabilities. No problem with equal variances. (c) Normality: If you pool the residuals, then plot a histogram or quantile-quantile plot, you see some deviations from normality: there are some especially small values. If you look at each group separately, you see some groups that seem normal and others that do not. I think there is a problem with normality. Other well justified answers were accepted. 3 0 3 5 4 0 4 5 -2 5 -1 5 -5 0 5 1 0 P re d i c te d R e sid u a l -3 -2 -1 0 1 2 3 -2 5 -1 5 -5 0 5 1 0 T h e o re ti c a l Q u a n tile s S a m p le Q u a n tile s 2) Marker effects in a genome-wide study (a) 10 Markers: numbered 1-10 Here are my computations: marker pvalue adjP 7 0.000 0.004 9 0.000 0.013 1 0.001 0.046 5 0.002 0.046 3 0.002 0.040 6 0.003 0.053 2 0.004 0.050 8 0.004 0.051 4 0.005 0.052 10 0.005 0.047
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Statistics 500 – Fall 2009 Solutions to Homework 5 2 63 0.008 0.071 73 0.009 0.072 24 0.010 0.073
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