EE 311 Final Exam_fall09_solution

EE 311 Final Exam_fall09_solution - 1 ` Name_Solution_ EE...

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1 ` Name_____________Solution_______________ EE 311 Final Exam Fall 2009 December 18, 2009 Closed Text and Notes 1) Be sure you have 16 pages. 2) Write only on the question sheets. Show all your work. If you need more room for a particular problem, use the reverse side of the same page. 3) Write neatly, if your writing is illegible then print. 4) This exam is worth 200 points. Name _____________________________
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2 Problem ABET Outcome Points Score 1 6 2 5 3 6 4 6 5 v 8 6 12 7 12 8 10 9 iii 10 10 10 11 10 12 vi 15 13 vi 20 14 10 15 iv 15 16 45 total 200
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3 (6 pts) 1. Convert the point (2, 2, 1) in rectangular coordinates to spherical coordinates. 22 11 1 221 3 tan tan 2 2 1 tan 1 45 o r q j -- - =+ + = + == (5 pts) 2. In spherical coordinates, a unit normal vector to the plane 60 o θ = is A) a r B) a C) a φ D) none of the above (6 pts) 3. The intersection of the surfaces defined by ρ = 10 and 4 z = is a a) a point b) a straight line c) a circle d) a plane e) a cone d) a cylinder
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4 (6 pts) 4. In free space a plane of charge 8.854x10 -12 C/m 2 is located at z = 1 m. The electric field intensity at the origin is, a) 8.854x10 -12 ˆ a z V m b) -8.854x10 -12 ˆ a z V m c) 1 ˆ a z V m d) - 1 ˆ a z V m e) none of the above
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5 (8 pts) 5. The sliding rod in the following figure is being pulled in the +x direction as shown at 3 m/s on two rails that are separated by 1m. Everywhere is a magnetic flux density of ˆ 5 z a T (5 pts) What is the current flowing through the resistor? =, = 5 ( ) =5 5 ( 1) 15 (1) Meanwhile, 10 (2) From (1) L S zz S L d Ed l Bd S dt d ad sa dt d S dt d x dt l I ⋅− −− = ⋅=   and (2), I=1.5 A, counterclockwise. (3 pts) With an arrow on the figure indicate the direction the current is flowing. See figure. 10 1 m 3 m/s x y
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6 (12 pts) 6. For the currents and closed paths shown, calculate the value of the indicated integrals.
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EE 311 Final Exam_fall09_solution - 1 ` Name_Solution_ EE...

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