Day 3.3 - Translation 3 - 1 0 p = 1 o0 ^ y0 ^ x0 2 q = 1 0...

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Translation 3 1/9/2012 11 q 0 expressed in {0} 0 ˆ x 0 ˆ y 0 o { } 0 = + = + = 1 2 1 1 0 3 0 0 p d q = 1 1 0 p = 1 2 0 q
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Translation 3 1/9/2012 12 3. the translation vector can be interpreted as an operator that takes a point and moves it to a new point in the same frame d
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Rotation 1/9/2012 13 suppose that frame {1} is rotated relative to frame {0} 1 ˆ x 1 ˆ y 0 ˆ x 0 ˆ y 1 0 o o = θ sin cos
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Rotation 1
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Day 3.3 - Translation 3 - 1 0 p = 1 o0 ^ y0 ^ x0 2 q = 1 0...

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