# 25Jan - and then multiply this ratio by 1 2 3 and 4.giving...

This preview shows pages 1–18. Sign up to view the full content.

25Jan Page 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
25Jan Page 2
25Jan Page 3

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
25Jan Page 4
25Jan Page 5

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
25Jan Page 6
25Jan Page 7

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
25Jan Page 8
25Jan Page 9

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
25Jan Page 10
25Jan Page 11

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
25Jan Page 12
25Jan Page 13

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
25Jan Page 14
Tofollow up from lecture. ... Basicallyone takes the present angle (in this case 2 π ), divide it by the number ofroots requested (here, 4)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: and then multiply this ratio by 1, 2, 3 and 4. ..giving us 2 π /4 [j],4 π /4 [ ‐ 1], 6 π /4 [ ‐ j]and8 π /4 [1]. Similarly, the cube roots of 1 are at angles of 2 π /3, 4 π /3 and 6 π /3 (=2 π =0). 25Jan Page 15 25Jan Page 16 25Jan Page 17 25Jan Page 18...
View Full Document

## This note was uploaded on 02/12/2012 for the course ECE 202H taught by Professor Talavage during the Spring '11 term at Purdue.

### Page1 / 18

25Jan - and then multiply this ratio by 1 2 3 and 4.giving...

This preview shows document pages 1 - 18. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online