11_digital - Digital Information Binary Coding Digital Sampling CDs and DVDs UCSD Physics 8 2 Binary Numbers for Digital Representation Though we

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Digital Information Binary Coding Digital Sampling CDs and DVDs UCSD: Physics 8; 2 Binary Numbers for Digital Representation Though we use base-10 for numbers, this isn't the only choice base 2: 1's and 0's only 0 00000000 (8-bit) 1 00000001 (8-bit) 2 00000010 (8-bit) 3 00000011 (8-bit) (1 + 2) 4 00000100 (8-bit) 127 01111111 (8-bit) (1 + 2 + 4 + 8 + 16 + 32 + 64) If we want to represent negative numbers, we could make up some rule, like: 127 11111111 (8-bit): first bit indicates negative This is one of several representations (esp. for handling negative numbers) UCSD: Physics 8; 2 How Binary Works: Instead of a 1's place, 10's place, 100's place, etc. which is 100 place, 101 place, 102 place, etc. for base ten We have a 1's place, 2's place, 4's place, 8's place... which is 20 place, 21 place, 22 place, 23 place, etc. for base 2 In decimal, when we get to 9, we've run out of digits next number is 10 after 9999 is 10000 In binary, when we get to 1, we've run out of digits next number is 10 after 1111 is 10000 UCSD: Physics 8; 2 Example: Binary to Decimal What is 01101011 in decimal? we'll ignore our special rule for negative here: only positive By analogy, what does 642 mean? 6 100's plus 4 10's plus two 1's 6 102 + 4 101 + 2 100 01101011 is then: 0 27 + 1 26 + 1 25 + 0 24 + 1 23+ 0 22+ 1 21 + 1 20 0 128 + 1 64 + 1 32 + 0 16 + 1 8 + 0 4 + 1 2 + 1 1 64 + 32 + 8 + 2 + 1 107 UCSD: Physics 8; 2 Example: Decimal to Binary Let's represent 99 in binary form By analogy, in decimal, we don't need any thousand's-place, or hundred's place (these are zero) meaning you could write 99 as 00000000000099 99 is not big enough to need any of the higher places We do need 9 10's, then left over with 9 If in binary, we have a 128's place, 64's place, etc.: then 99 doesn't need a 128: 128 is too big but does need a 64, leaving 35 remaining 35 needs a 32, leaving 3 remaining 3 does not need a 16, 8, or 4, but does need 2, leaving 1 remaining 1 needs one 1 to finish out So result is 01100011 UCSD: Physics 8; 2 How many digits/bits 3 decimal digits lets you represent 0999 1000, or 103 possible numbers Generally, N decimal digits gets you 010N - 1 10N possibilities 3 binary digits gets you 07 (23 = 8 possibilities) 000, 001, 010, 011, 100, 101, 110, 111 In general, N binary bits gets you 2N possibilities In a similar way, a license plate with a format ABC 123 has (26) (26) (26) (10) (10) (10) = 17,576,000 possibilities enough for most states UCSD: Physics 8; 2 Adding Binary Numbers Same rules apply as for adding decimal numbers: when you exceed the available digits, you "carry" extra digits Let's add 46 and 77 00101110 and 01001101 11 00101110 = 2 + 4 + 8 + 32 = 46 + 01001101 = 1 + 4 + 8 + 64 = 77 0 1 1 1 10 1 1 = 1 + 2 + 8 + 16 + 32 + 64 = 123 The rules are: 0 + 0 = 00 1 + 0 = 0 + 1 = 01 1 + 1 = 10 (0, carry a 1) 1 + 1 + 1 = 11 (1, carry a 1) UCSD: Physics 8; 2 Digital Representation of Analog Quantities Sound waveform can be digitized At uniform time intervals, amplitude of waveform is characterized by an integer number 8-bit (from 127 to 127) (low resolution) 12-bit (from 2047 to 2047) 16-bit (from 32767 to 32767) (high resolution) sound amplitude sound waveform time digitized sample points, uniform in time UCSD: Physics 8; 2 Digital Audio Formats Must sample at greater than twice the highest frequency you want represented in the sound clip Human hearing sensitive up to 20,000 Hz CDs recorded at 44,100 Hz (44,100 samples/second) Must have reasonable resolution (fine-grain) 8-bit has only 42 dB dynamic range (sounds grainy) 16-bit has 84 dB range: CD's at 16-bit Stereo is usually desirable (separate waveforms) CD's then read 2 44,100 16 = 1.4 million bits/sec in familiar units: 1411.2 kbits/sec 74-minute disc then contains 6.26 billion bits = 783 MB one second of CD music contains 176 kB of data data CDs use some space for error correction: get 650 MB UCSD: Physics 8; 2 All that information on one little disk?! CDs are truly marvels of technology Data density: 6.26 billion bits over R2 area R = 60 mm = 60,000 m A = 11 billion m2 0.55 bits per micron-squared: 1.34 micron square per bit Bits arranged in spiral pattern from center out Outer 40 mm / 1.34 micron 30,000 wraps 74 minutes = 4440 seconds 67 revolutions per second Bits Pits pressed into aluminum foil Pit digital 0; No pit digital 1 UCSD: Physics 8; 2 Arrangement on the CD Pits are arranged in long spiral, starting at center and spiraling outward toward edge Are pits bits? Are non-pits bits? UCSD: Physics 8; 2 Read-out Mechanism Laser focuses onto pit surface Reflected light collected by photodiode (light sensor) Intensity of light interpreted as bit value of zero or one Separate side beams ensure tracking "ride" between adjacent tracks on spiral polarizing beamsplitter separates outgoing from incoming light UCSD: Physics 8; 2 The real deal... UCSD: Physics 8; 2 Optical Requirements Pits are small! micron size; laser wavelength is 0.78 m Cannot (quantum-mechanically) focus laser smaller than its wavelength and have to work real hard to come close UCSD: Physics 8; 2 Noise Immunity Can scan ahead (array of detectors) Build up multiple-reads of same block Hardly affected by dust/scratches on surface beam is 0.51 mm in diameter as it encounters disk most of beam sees around dust or scratch pits actually only 0.11 m deep 1.2 mm 0.8 mm UCSD: Physics 8; 2 Why All the Fuss? Why Go Digital? Sound, images are inherently analog: sound is continuously variable pressure amplitude light is represented by a continuum of wavelengths and brightnesses But reproduction of these with high fidelity would require precision recording, precision equipment exact height of ridges in vinyl record groove critical exact signal strength of radio wave determines brightness of pixel on TV screen device-dependent interpretation (tuning) subject to variation Digital information means unambiguous data CD pit is either there or it isn't Electronically handled as 0V or 5V: easy to distinguish everybody has access to the full-precision information UCSD: Physics 8; 2 DVD Technology DVDs make many leaps beyond CD technology: 0.65 m laser: the better to see you with smaller pitsgreater data density can be double-sided double layer in some cases (4 layers altogether) data compression Density of pits up 4 times, plus 4 surfaces holds 16 times as much as CD Data compression extremely important for DVDs avoids redundant coding of repetitive information (e.g., still scenes, backdrops, even music waveforms) UCSD: Physics 8; 2 Data Compression Two types: lossless and lossy Lossless examples zipped computer files, GIF images, stuffit can completely recover error-free version of original toy example: 00010001000100010001000100010001 notice 0001 appears 8 times could represent as 10000001, where first 4 bits indicate number of times repeated, second four is repeated pattern compresses 32 bits into 8, or 4:1 compression ratio Lossy examples JPEG, MP3, MPEG look/sound okay, mostly by cheating ignoring information they eye/ear is not adept at noticing irrecoverable errors introduced into data UCSD: Physics 8; 2 Audio Compression Imagine a perfect sine wave could represent this as lots of samples (many bits) or could represent as frequency and amplitude (few bits) MP3 recipe break into short bits (576 samples) shorter (192) when something abrupt is happening characterize frequencies and amplitudes present represent as fewer numbers of bits if one frequency dominates, can ignore the rest ear's limitation allows us to do this achieve compression of about 11:1 UCSD: Physics 8; 2 References & Assignments References: How CDs work: http://electronics.howstuffworks.com/cd.htm DVDs: http://electronics.howstuffworks.com/dvd.htm MP3: http://computer.howstuffworks.com/mp3.htm also: http://en.wikipedia.org/wiki/Mp3 http://computer.howstuffworks.com/file-compression.htm iPod: http://electronics.howstuffworks.com/ipod.htm Assignments HW4, due 5/11: 11.E.16, 11.E.19, 12.E.13, 12.E.14, 12.E.15, 12.E.16, 12.E.17; plus 6 additional required questions accessed through assignments page on website ...
View Full Document

This note was uploaded on 02/12/2012 for the course PHYSICS 104 taught by Professor Staff during the Fall '10 term at Rutgers.

Ask a homework question - tutors are online