11.14 - Section 4.1 (continued): Theorem 3 (Extreme Value...

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Section 4.1 (continued): Theorem 3 ( Extreme Value Theorem ): If f is continuous on the closed interval [ a , b ], then there exist c and d in [ a , b ] such that f ( x ) f ( c ) for all x in [ a , b ] and f ( x ) f ( d ) for all x in [ a , b ]. That is, every continuous function whose domain is a closed interval must have a global maximum value f ( c ) and a global minimum value f ( d ). Last time we saw that the hypothesis of continuity cannot be dropped. Is the Extreme Value Theorem still true if the domain is the open interval ( a , b ) instead of the closed interval [ a , b ]? ..?. . No; e.g., f ( x ) = x on (–1,1), or f ( x ) = x 2 on (0,1). It’s hard to prove the Extreme Value Theorem; I may say more about this at the end of the semester, if time permits (and enough of you are interested). Like the Intermediate Value Theorem, it can be derived from the Cut Axiom. How do we find global maxima and minima for a function on a closed interval? We look at endpoints and local maxima and minima.
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How do we find local maxima and minima? We look at all the critical points . Definition: A critical number of a function f is a number c in the domain of f such that either f ( c ) = 0 or f ( c ) does not exist. Fermat’s Theorem
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This note was uploaded on 02/13/2012 for the course MATH 141 taught by Professor Staff during the Fall '11 term at UMass Lowell.

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11.14 - Section 4.1 (continued): Theorem 3 (Extreme Value...

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