{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

CH 301 FUND Ch4 notes part 1 answers

# CH 301 FUND Ch4 notes part 1 answers - CH301(4 Notes part 1...

This preview shows page 1. Sign up to view the full content.

CH301(4) Notes part 1 answers 1. Calculate the molarity of a solution that contains 12.5 g of sulfuric acid in 1.75 L of solution. Note here we must covert moles to grams: 4 2 4 2 4 2 4 2 4 2 4 2 SO H 0728 . 0 L SO H mol 0728 . 0 SO H g 98.1 SO H mol 1 n sol' L 75 . 1 SO H g 12.5 n sol' L SO H mol ? M u 2. Determine the mass of calcium nitrate required to prepare 3.50 L of 0.800 M Ca(NO 3 ) 2 . 2 3 2 3 2 3 2 3 2 3 ) Ca(NO g 459 ) Ca(NO mol 1 ) Ca(NO g 164 L ) Ca(NO mol 0.800 L 50 . 3 ) Ca(NO g ? u u Note: you would NOT add this to 3.5L of water, but use the method shown previously: add sufficient distilled water to the dissolved solid to make the volume 3.5L Dilution example 1: We take 5ml of a 0.1M solution of HCl and place it in a 100ml volumetric flask, and dilute to the mark with distilled water. What is the concentration of the new HCl solution?
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}