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MCE311
Homework # 1
Due on Monday, Feb 28
th
, 2011.
Question 1 (6.1)
A certain length measurement is made with the following results:
Reading:
1
2
3
4
5
6
7
8
9
10
X(cm):
49.3
50.1
49.0
49.2
49.3
50.5
49.9
49.2
49.7
50.2
a)
Arrange the data into bins with width 2 mm.
b)
Draw a histogram of the data.
Solution
6.1
a) Data arranged in bins with width 2mm
Question 2
(6.43): A voltmeter is used to measure a known voltage of 100V. Forty
percent of the readings are within 0.5 V of the mean value. Assuming a normal
distribution for the error, estimate the standard deviation for the voltmeter. What is the
probability that a single reading will have an error greater than 0.75V?
Solution
6.43
The area from 100 to 100.5 is 0.2. From Table
6.3, z =
0.52
96
.
0
,
100
5
.
110
52
.
0
Probability of error greater than 0.75 Volts:
z
100 75 100
096
078125
.
.
.
b)
0
1
2
3
No. Meas.
48.7 48.9 49.1 49.3 49.5 49.7 49.9 50.1 50.3 50.5 50.7
Length range  cm
No. meas. 10, bin width 2 mm
Bin
(cm)
Number of
Measurements
48.949.09
1
49.149.29
2
49.349.49
2
49.549.69
0
49.449.89
1
49.950.09
1
50.150.29
2
50.350.49
0
50.550.69
1
99.5
100
100.5
20%
20%
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View Full DocumentFrom the normal distribution curve(Table 6.3) for
z = 0.7812
P(z) = 0.2826
for error greater than 100.75 or less than 99.25 (100
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 Spring '11
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