PGE 421K Spring 2010 HWSolution7

PGE 421K Spring 2010 HWSolution7 - PGE 421K Spring 2010...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: PGE 421K, Spring 2010 HOMEWORK 7 Solutions 1) Wells in a certain gas reservoir have productivity index PI in the range 4×10-4 to 6×10-4 MSCFD/psi 2 . The initial reservoir pressure was 866 psia. Based on cumulative production you estimate the average reservoir pressure is now 635 psia. When you started up the field, you set the wellhead pressure so that the flowing bottomhole pressure P bh was 435 psia. The wellhead pressure has not changed appreciably since startup, so you are assuming that P bh has not changed either. The wells produce 8 to 10 bbl water per MMSCF of gas. a. What was the range of gas production rates after the field started up? gG = ¡ ¢£¤ g ¥ − g ¦§ ¥ Solve for ¡ ¢£¤ : ¡ ¢£¤ = gG¨g ¥ −g ¦§ ¥ © For gG = 0.0004 ª«¬­® ¯°± ² and 0.0006 ª«¬­® ¯°± ² , g = 866 ³´µ¶ , g ¦§ = 435 ³´µ¶ : ¡ ¢£¤ = 4 × 10 ·¸ ¨866 ¥ − 435 ¥ © = 224 ¹º»¼½ ¡ ¢£¤ = 6 × 10 ·¸ ¨866 ¥ − 435 ¥ © = 336 ¹º»¼½ b. What range of gas production rates should you be getting today, based on your assumption about P bh ? For gG = 0.0004 ª«¬­® ¯°± ² and 0.0006 ª«¬­® ¯°± ² , g = 635 ³´µ¶ , g ¦§ = 435 ³´µ¶ : ¡ ¢£¤ = 4 × 10 ·¸ ¨635 ¥ − 435 ¥ © = 86 ¹º»¼½ ¡ ¢£¤ = 6 × 10 ·¸ ¨635 ¥ − 435 ¥ © = 128 ¹º»¼½ c. If water has accumulated to a height of 50 ft above the perforations in each...
View Full Document

This note was uploaded on 02/13/2012 for the course PGE 421K taught by Professor Bryant during the Spring '11 term at University of Texas.

Page1 / 4

PGE 421K Spring 2010 HWSolution7 - PGE 421K Spring 2010...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online