ESP - PCP Design Example

ESP - PCP Design Example - PGE 362 ESP or PCP Design...

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PGE 362 ESP or PCP Design Example Data: 1 1 2 2 -5 1.0 1 STB/Day/psi Well Tests: 500 STB/Day 2000 psi 750 STB/Day 1750 psi Perforation Depth = 7,000' Tubing = 2 7/8" OD x 2.441" ID Tubing Friction 2x10 psi/ft/BPD Separator pressure L wf wf J q p q p γ = = = = = = 2245 ( 29 ( 29 3 required at the surface = 50 psi. ESP or PCP performance: 8.9 10 76.7 rate STB/Day output pressure head ft of fresh water/stage Number of stages = 100 The fluid level must stand 100' above the p H x q q H - = - + = = ump depth during operation. The average reservoir pressure can be calculated from the well tests: 500 750 2000 1750 2500 psi p p p = - - = Reservoir performance is described using the productivity index: 1 2500 2500 wf wf wf q J p p q p p q = - = - = -
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The flowing bottom hole pressure can be related to the liquid level inside the well using: ( 29 ( 29 ( 29 ( 29 0.433 7,000 100 pump depth ft 0.433 7,000 100 2500 2500 0.433 7,000 100 0.433 487.7 .......... (1) wf L L L p D D D q q D q D γ = - - = - - = - = - - - = - The pump output can be described using ( 29 3 3 8.9 10 76.7 100 8.9 10 76.7 0.433 psi out L H x q p x q - - = - + = - + = The pump output pressure must overcome lift losses to the separator.
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This note was uploaded on 02/13/2012 for the course PGE 362 taught by Professor Bommer during the Spring '08 term at University of Texas.

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ESP - PCP Design Example - PGE 362 ESP or PCP Design...

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