HWK 6 solution - PGE 362 Homework 6 Solution Due at the...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
PGE 362 Homework 6 Solution Due at the start of lecture on April 6th. Data Set: 6 1 psi/ft 0.65 psi/ft =0.6 10,000' 1 10 psi 0.15 V pore p D E x v σ α = = = = = (1) Please compute the three principle stresses at the given depth. ( 29 ( 29 ( 29 ( 29 ( 29 Hmin Hmax 10,000 1 10,000 psi 10,000 0.65 6,500 psi 0.15 10,000 0.6 6500 0.6 6500 4,976 psi 1 0.15 10,000 4976 7488 psi 2 V pore p = = = = = - + = - + = = (2) For a vertical well please determine (a) the break out pressure at the well ( 29 min max 3 3 4976 7488 6500 940 psi b H H pore p p = - - = - - = (b) the break out fracture direction (c) the far field (natural) fracture direction You may neglect tensile and thermal stresses. The break out and far field directions are identical and will be perpendicular to the direction of the minimum horizontal stress.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
(3) For a horizontal well drilled parallel to the maximum horizontal stress please determine (a) the break out pressure at the well ( 29 min 3 3 4976 10,000 6500 1572 psi b H V pore p p σ
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 02/13/2012 for the course PGE 362 taught by Professor Bommer during the Spring '08 term at University of Texas at Austin.

Page1 / 3

HWK 6 solution - PGE 362 Homework 6 Solution Due at the...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online