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Unformatted text preview: Math021, week 14 Definition 14.1 A series ∑ ∞ n =1 a n converges absolutely if ∑ ∞ n =1  a n  converges. Theorem 14.2 A series converges if it converges absolutely. proof: Let ∑ ∞ n =1 a n be a series which converges absolutly. Define a + n = max { a n , } , and a n = max { a n , } for all n . Then, 0 ≤ a + n ≤  a n  for all n and since ∑ ∞ n =0  a n  converges by hypothesis, we conclude that ∑ ∞ n =1 a + n converges by comparison test. Similarly, ∑ ∞ n =1 a n converges. Therefore, ∞ X n =1 a n = ∞ X n =1 ( a + n a n ) converges also. Example 14.3 Determine if the series ∞ X n =1 ( 1) n n 3 / 2 converges. solution: Since ∞ X n =1  ( 1) n n 3 / 2  = ∞ X n =1 1 n 3 / 2 converges from a certain previous example, ∞ X n =1 ( 1) n n 3 / 2 converges absolutely. Hence, it converges. Power Series 1 Definition 14.4 A power series is a function f defined by f ( x ) = ∞ X n =0 c n ( x a ) n for certain numbers a , c , c 1 ,.... We also say that such a power series is centered at a . Example 14.5 The function f defined by f ( x ) = ∞ X n =0 x n is a power series centered at . It is a geometric series with common ratio x . Hence, f ( x ) = 1 1 x when  x  < 1 . We also know that the series defining f diverges when  x  > 1 . Therefore, f is defined over ( 1 , 1) . Theorem 14.6 Let f ( x ) = ∞ X n =0 c n ( x a ) n be a power series centered at a . There is a number R ≥ , called the radius of convergence of the given series, so that the series converges absolutely when  x a  < R , and the series diverges when...
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 Fall '10
 LUXNU
 Math, Taylor Series, Taylor Series Theorem

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