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QUIZ 2 KEY - CHM 2046‘ QUIZ 2 Name Section TA K E Z...

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Unformatted text preview: CHM 2046‘ QUIZ 2 Name . Section TA K E Z ' Possibly Helpful Information: —bi b2 —4ac For 0=ax2+bx+c, x: 2a Kp = Kc (RT)Ang R = 3.314 J/mol K = 0.08206L atm/mol K You may use the handout “Relative Strengths of Acids and Bases” on this quiz. 1. (10 pt) Calculate the value of K for these reactions: W K v VOVCMM \ eat/k. Takte/ 0“" -' LA" (21) $03"2+H20 V—_x 1150; + OH‘ K ~ Eu) Lower” ._. : ——-—————-———:'@ Kovx’ Q], xlo 1“:_._...L_G__)<__l,0 _ g— (h) (. O ' ~1- H; ( ()3 a: 2 H( 0 _ - C) H 7__1“co:,>+vkt 0 5) lESOyl'HC’Ost 11“! m3— 1.;{1 Dc“) (—QOfl—COE- Lee—L Magi G [:0 7/@ + 310.4ny '2, c: t1» ‘ 3650 t 9+; H00 —+ :2: Lecféo e) M; + sz' no» 07' '7— ”Mace K= _ _ H1003 + C03 (3 _ raw . 2. (10 pt) Calculate the value of Kc for this reaction at the temperature indicated NH4HS (S)\—- —‘ HZS(g) + NH3(g), Kp = 0.11 at 250°C KC: hf (emflma lac : out“) 9811 fim )(150+2?3)l<] REM Ham Q Viz/O g Hy WV“ 3 (25 pt) What are {1130+}, [03:1,de the pH for each solution? : X (0 (a) 0,025 M.*wea{c acid K“ R '8 ~40 J. mm (Q ma co MW W FHzr TE T50 La :m‘5 :54 Gym/‘0) <uo {Haoflfioq 3 Oxta 4 (OH '15 Lfl‘ifii 3 (bxto'b {11301=?2 ,;x we JOE—F .2 :Q‘3 =‘5J6 (b) 0.08MNazggé 7/ Marx 3051‘ 3031‘ 7"}{1/0 (53’ HsOE +01» use-{Q «m: K (O K : Kw : two—“‘9 {QmQ “r Q (751C g/gxw‘ H A . L Y 80‘ 1 [00‘] Q10 XK 2Y1 “r [0‘08 X Qwa‘gj (OH—:3 5 W {11'30+1=3_>§ zo'“H low: “We “4 H pn.—._ I0. I approximate or “shortcut” method. Rather, a quadratic soluTion must be found. (A calculated answer is not required.) 0.005 M NH4C1 ( 0.0050 M HNOz > 0.050 M NazSO3 2“. Nagy“ Pr ZNoJ‘SOg ...
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