This preview shows pages 1–14. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: ASE 362K, Assignment No 4 1) 2) 3) 4) 5) 6) Thursday, Februag 7, 2008 Review the section in Anderson on normal shock waves. A blunt nosed projectile is moving at Mach 4 at sea—level where the static pressure
P = 1 atmosphere, and the static temperature T = 20°C. What is the projectile speed in m/s? What are the static pressure, static temperature and the velocity downstream of the
normal shock wave? What is the Mach # downstream of the wave, M2? How much does the downstream Mach number change if we double, then
quadruple the ﬂight Mach #? e) What is M2 if we accelerate to M1 = 00? This question, on the attached sheet, is from Quiz #1, given when I taught this class in
spring 2006. It was in the closed book part. Try it without using your notes. Note that
to answer these questions you don’t have to remember normal shock equations and be
able to do complicated arithmetic in your head. . . ..you just need to bear in mind the
conservation equations and other basic things that are “fundamental” to normal shock
waves such as the stagnation temperature is constant across the wave, the stagnation
pressure goes down etc ...... ..and which should be second nature to you. A normal shock occurs in a ﬂuid which is not a perfect gas. In fact, the pressure and density are related by the expression p [dp/dp] = c, where c = a constant. Show that in this case the upstream and down stream Mach numbers are related by the equation
log (MK/M22) = M12 — M22. The cylinder on the right is ﬂying at
sea—level. (P1=latm=105 Nm"2).
Given that the drag comes entirely
from the pressure on face "A", what
is the ratio of the drag at Mach 3 to
that at Mach 0.8? [You can assume
the pressure on face A is uniform]. A normal shock wave is, in essence, a thermodynamic process (namely a
compression) and the change in properties across it can be expressed solely in terms
of thermodynamic variables, rather than introducing a "ﬂow" quantity, the Mach #. P,+P,F_1_ il
2 p1 [Uzi
2 (y—l)+(y+1)%
p1_(y+1)+(y_1)%' Show that the change in internal energy can be written as 62 — 61 = and that the density ratio can be written as In a student laboratory measurements are being made downstream of a normal shock
wave. The conditions upstream of the shock wave were measured by the instructor and
are all correct. The wave forms in air for which R = 287J/kg, Cp = 1005 J/kg and y = 1.4.
Some of the measurements are shown on the attached sheet. If you think an error has
been made say so and indicate the error, or errors. If you think the measurements are okay, say so (NN points). Note: no answer = no points) N5 Anstner ml&
6;) 'NS
1 ‘ial'm ileaézqgéﬁ [(9le
T‘ 2 390K 'qlgzsafsglg
u‘,:, Soomls . .
H‘ =. 15 0.0 Ms
“1:1 . “1' 0‘53"?
PrMm a . assign N5
Q) [1,41 Hi=o~zz$f
(Di—‘44:. P; = to 33m. 1] \5 \Su3\ VOATM? (don‘me . Wm could do (\r «(a \‘ke 70.5?» (Back ‘3 0v via
‘1“, ‘WWW N‘na'e («Icahn2  of \SMaV ‘75
make WW9 W Max» uukak Sam M MM‘/§\A‘q\’\~§6 8m (OM/(0‘ A0 (L ’—'.S£L ‘iibc\a~ a3 Hos = Vw/ouu So VaQ = am H00
1. ad, = E (\.+>(23?>(2°\1>3" b HoQ =
\nbna "' [27'1 ~l3 Kim: was r3= 1352M.“ 1 “(min (um; ‘iHS’W HY?“ = “a w (“1‘5 ("900 H} g (,,eq)"l x o'H‘ES‘
UL — 011”; " ‘69‘3 M"
c [(c.w)(zn>(ug§})1“z (0%“)
__ ‘goo 2 ~15 9
~\ C looo~l5 oLfc/z. .K'VJ'P‘ocHs —— Scwg
decMWako‘L. EB H PM «BM M‘ ‘ 14 r72 =. O'Lf‘Ss.
m, z I6 Hz =o'3gz
how Ma}. ‘ \‘V (0'1) “‘1
thF  0 ‘2
on H\ "> a“ i <“ ‘1"1~Z
o2. <<< \HHf‘ “ H I) E12 Wen‘ SWuaLT—ws) m cow. Cheri. wkeﬂv
‘oaw; (noun ‘LW Kn com ~
uxbkaFdJ W 0&0 CWQBMF.) v..o\o,FEd_ cox/~51» oaa LEV. Q.) M do (‘6‘. WM (3‘ W P\ So check E 5&2 H" onme km 196%. duv'aE‘ol How
about)!“ wuss CT‘H “T” ‘37
TBA 2. T4 \6:\ “‘1
‘2.
’— 3°°E ‘+ ('2)(‘+)3  s‘HOkr
T01. = T; {1+ \6':\ NJ)
1 .
= 60%(\ + (2>(5??>1> = gmfﬁ T04 w (Wredv (5mm M) N,
5° 5M? Hvwb WW.» B1 WW5 unuk.
€‘hnu HA w T; C H' (mm; cud hab G 5 we are
(Md (>.l amo! L41 5.: we.
562. lé‘ CWFMah—s (LEM; : C'2~O§Q>(28w.g> k3 [N15
_ 5%3’242... P‘
a?) 0‘ 5 " = 1013;00 (Soc) (ZEDC 30°) 63)”) z ‘
‘1: “> I/ 6
HM
118/1000 .3 OWL? 4 \/6 N M (Md (QJMa/E 90‘ aﬂJk—xgaw
(Wk dM;LIfO§M % ‘ —. Pox ‘— 10) (H L H‘>3.> \l
J
3
p
9
H H“; \ L
5W9 ’6 p03 Ca‘vadr ? €°l. acre): ox nw~a\ skew/L. WW _C__ Sum (21. =SIIQ’LQ
G, . be, 6 can ‘ '2. 'z.
0450‘ r. Cielf ' 0:,
swﬁ uz: Hiaz a, [773 (puz z. 9H1}; = Ch"
6  F '
Or (A = Cﬂz ._.——— 6
f, (A _ *.. 'L h 7. 5 w ch‘rwwu G F’ ’1: 1 J u has @ \‘5 C} M. at .. Eda”!
cc P01:— P.Ll+‘6;‘M23
L 3'8’
,1 P. [er (2>('64)3
= lSzH P. “WMC ULR“ ‘31 a ﬁOvrwn‘ At H :30 shod» NW6 akeé‘d «5 («ma Pr aw» fa“ A w\‘\ H! We (RanQWh—s pPPJDM 3 WC
“M Amsmm 3 the skocL WM oi FOL. . EO} ak H13 W's) :— 0.3183 Pas
7’“ PUA=er11
'2.
3 ,
P01 . PL (l+(z>(o.>> b 9 We! ux w; mmeML—m eag Miz ”’ PLP‘ (71> ®
ez~e\ ez ...
View
Full
Document
 Spring '07
 DOLLING,D

Click to edit the document details