Unformatted text preview: 2 x (12 x ) ( x 2 + 1) 2 = 1212 x 2 ( x 2 + 1) 2 . At a maximum A ( x ) = 0, i.e. , 1212 x 2 ( x 2 + 1) 2 = 0 , i.e. , A ( x ) = 0 when x = ± 1. On practical grounds the positive solution corresponds to maximum area, while the negative solution has no meaning for this problem. Consequently, the maximum area = A (1) = 6 sq. units. . keywords: optimization, maximize, rectangle, area, word problem, 012 (part 1 of 1) 10 points If the graph of f is which one of the following contains only graphs of antiderivatives of f ? 1. 2....
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 Spring '08
 CLARK,C.W./HOY,R.R
 Optimization, max area, sq. units

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