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17. Use the properties of logarithms to ﬁnd the exact value of the expression. I guess you problem
is ﬁnding the value of the following expression
2 log3 +3 log2 − log2
6
6
6 (1) OK, let look at the expression again, we ﬁnd that the second term and the third term contain the
same log2 , hence we get 3 log2 − log2 = 2 log2 Then we expression (1) will become
6
6
6
6
2 log3 +2 log2
6
6 (2) and then we see that we can factor out number 2, thus
2(log3 + log2 )
6
6 (3) If we use the properties of logarithms– sum of log=log of product
2(log3 + log2 ) = 2 log6 (3 × 2) = 2 log6 = 2 × 1 = 2
6
6
6
Hence the solution is (e).
huyu@math.byu.edu (4) ...
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This note was uploaded on 02/14/2012 for the course MATH 110 taught by Professor Staff during the Fall '08 term at BYU.
 Fall '08
 Staff
 Algebra

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