Lecture-5 - x = ln( y + p y 2-1) , y > 1 for y . Answer:...

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Math 137, Lecture 5, Wednesday September 17, 2008 (Stewart, pages 52-63) Exercises for Student: 1. Solve the equation
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Unformatted text preview: x = ln( y + p y 2-1) , y > 1 for y . Answer: y = 1 2 ( e x + e-x ) 2. Solve log 3 | 3-2 x | = 2. Answer: x = 6 or x =-3 1...
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This note was uploaded on 02/14/2012 for the course MATH 137 taught by Professor Speziale during the Spring '08 term at Waterloo.

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