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Lecture-5 - x = ln y p y 2-1 y> 1 for y Answer y = 1 2 e...

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Math 137, Lecture 5, Wednesday September 17, 2008 Topic: Exponential & Logarithmic Functions (Stewart, pages 52-63) Exercises for Student: 1. Solve the equation
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Unformatted text preview: x = ln( y + p y 2-1) , y > 1 for y . Answer: y = 1 2 ( e x + e-x ) 2. Solve log 3 | 3-2 x | = 2. Answer: x = 6 or x =-3 1...
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