This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: -2 n 3. Part a: x [ n ] = U [ n + 2]-2 U [ n ] + U [ n-1] Part b: x [ n ] = ( n + 1) U [ n + 1]-2 U [ n ]-( n-1) U [ n-3] Part c: x [ n ] = [ n ]- [ n-1] + U [ n-2]-U [ n + 1] Problem 8 Part a: Any discrete-time signal can be expressed as x [ n ] = X k =- k [ n-k ] Find the coecients, k . (Hint: we did this in class) Part b: x [ n ] can also be expressed as a sum of unit-step functions x [ n ] = X k =- k U [ n-k ] Find the coecints, k . (Hint: [ n ] and U [ n ] are related). Problem 9 Problem 1.27 (a), (b), (c) 2...
View Full Document
This note was uploaded on 02/14/2012 for the course ECE 301 taught by Professor V."ragu"balakrishnan during the Fall '06 term at Purdue University-West Lafayette.
- Fall '06