CS1371_Spring_2010_FinalReview_Questions_Solutions

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Unformatted text preview: @E :_ BD? <F<> > > C <6? @ < C<=7?TAI 9 6> B N % Assume it is 3rd and 4th seconds inclusive Fs = 11000; thirdFourth = num(Fs*3:Fs*4); [ECT? CEA<C<=7?6<[Wbcd=<=\II 9B=<==6<CA: A 6<6 := 9 6> > < CN A e :@CN]CE 9= = < P hiQ jk fg P % Instructions are a little unclear. Assume raise % frequency by 2 half steps N = length(num); new = round(linspace(1, N, N/2.^(2/12))); newSound = num(new); [ECT? C=E> C<j m <CE6`LC =A 6AA:B>C\IIDa o]p6< A 6<6 9AG9 l l;T6 C n A C EH>B<H9 A O M ICE < K< = < CAA:;E:BZ rl lI 9=> :AO< q m new = round(linspace(1, N, N*3/5)); skData = data(new); st vxy { u z| &')),( + *. *) 01\$23 5 6!7\$\$ \$ 1 !4 \$ 8 1 To put 9999999the 9999999of999999999999 on size N 99it9simply, 999efficiency 9999999999999...
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## This note was uploaded on 02/15/2012 for the course CS 1371 taught by Professor Stallworth during the Spring '08 term at Georgia Tech.

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