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Unformatted text preview: MAC 2312 Quiz 3 January 31, 2012 SOLUTIONS 1. Evaluate the indefinite integral integraldisplay x 4 x 2 9 dx. Solution: Begin by using polynomial long division to writhe the integrand as follows: x 4 x 2 9 = x 2 + 9 + 81 x 2 9 . The given integral is therefore integraldisplay x 4 x 2 9 dx = integraldisplay x 2 dx + 9 integraldisplay dx + 81 integraldisplay 1 x 2 9 dx = x 3 3 + 9 x + 81 integraldisplay 1 x 2 9 dx + C. (1) It remains to compute integraltext 1 / ( x 2 9) dx . To do this, find the partial fraction decom position of 1 / ( x 2 9) as follows. First, write 1 x 2 9 = 1 ( x 3)( x + 3) = A x + 3 + B x 3 , (2) where A and B are to be determined. To determine A and B , multiply both sides of equation (2) by ( x + 3)( x 3) then rearrange terms to get 1 = A ( x 3) + B ( x + 3) = ( A + B ) x + 3( B A ) . From this, by matching coefficients of likepowers of x , we conclude that A + B = 0 and 3( B A ) = 1 ....
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This note was uploaded on 02/15/2012 for the course MAC 2312 taught by Professor Bonner during the Spring '08 term at University of Florida.
 Spring '08
 Bonner
 Calculus, Division

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