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p240+jan+18+discussion+problems

p240+jan+18+discussion+problems - r< a(b Derive the...

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Diagram for 22.34

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22.28 A conductor with an inner cavity, like that shown in Fig.22.23c from the textbook, carries a total charge of +5.00 nC. The charge within the cavity, insulated from the conductor, is -6.00 nC. (a) How much charge is on the inner surface of the conductor? (b) How much charge is on the outer surface of the conductor?
22.46 A conducting spherical shell with inner radius a and outer radius b has a positive point charge Q located at its center. The total charge on the shell is -3 Q, and it is insulated from its surroundings. (a) Derive the expression for the electric field magnitude in terms of the distance r from the center of the region

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Unformatted text preview: r < a . (b) Derive the expression for the electric field as a function of r for the region a < r < b. (c) Derive the expression for the electric field as a function of r for the region r > b . (d) What is the surface charge density on the inner surface of the conducting shell? (e) What is the surface charge density on the outer surface of the conducting shell? • In a certain region of space, the electric field E is uniform. (a) Use Gauss’s law to find the volume charge density in this region. (b) Is it necessary for a region to have a uniform E if the charge density is zero? (c) Explain your answer to part (b)....
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p240+jan+18+discussion+problems - r< a(b Derive the...

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