Unformatted text preview: If this child grows up, gets married, and has a child, what is the probability that their child will have trouble with bladder control? 0.5 * .12 * 0.5 = .03 [0.5 chance that carrier (fetus is known to be a carrier) will pass on mutated allele] * [0.12 chance that random individual in population is a carrier] * [0.5 chance that carrier will pass on mutated allele] If they have one child that has trouble with bladder control, what is the probability that they will have another child with bladder control problems? 0.5*0.5 = 0.25 If they had a child homozygous recessive for BC mutation, then they must both be carriers....
View Full Document
This note was uploaded on 02/15/2012 for the course PMB 13 taught by Professor Freeling during the Spring '09 term at Berkeley.
- Spring '09