ps3, prob 7

# ps3, prob 7 - B allele B Given child 2’s RFLP genotype...

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Problem 7. A witch has 9 children and wants to know which of them will grow up to develop magic powers. The ability to perform magic is caused by a dominant mutation in the boredom gene (B = magic allele; b = wild-type allele). She marries a man who also has magical powers. You know that both parents must be heterozygous at the magic gene, because both had a non-magical parent. The family comes to you for genetic counseling. You find a SNP that is 20cM away from the boredom gene that results in a RFLP. You know, from genotyping the grandparents, that the allele of the RFLP that doesn’t get cut is linked to the B allele in both the witch and her husband: A) Given child 1’s RFLP genotype, what is the probability she will be homozygous for the
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Unformatted text preview: B allele? B) Given child 2’s RFLP genotype, what is the probability she will be homozygous for the B allele? C) What is the probability that child 4 will be homozygous for the B allele? You find another RFLP that may or may not be close to the boredom gene. You decide to characterize it in another family and this time you genotype all of the grandparents, parents and children. The genotype and RFLP fingerprints are the same for both the mother’s parents and the father’s parents. D) Calculate the recombination frequency for this RFLP with respect to the boredom gene 7kb 4kb 3 kb Mother Father A B C D E F G H I Bb Bb BB bb Bb bb BB B B BB Bb Bb Grand-mother Grand- father BB bb 15kb 12kb 3 kb Mother Father 1 2 3 4 5 6 7 9 Bbb Bb 8...
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