ps1, prob 6

ps1, prob 6 - event whereas indicates that no plaques...

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Problem 6. You have isolated five deletion mutants in the T4 phage genes that control lysis of R bacteria. You infect R bacteria with pairwise combinations of these phage and determine whether they are able (+) or not able (-) to recombine and form wild-type phage that can infect the bacteria. The results are as follows: 1 2 3 4 5 1 - + - + - 2 + - + + - 3 - + - - - 4 + + - - + 5 - - - + - A) Construct a map of the deletions that fits the data in this table You find five point mutants (a to e) with the same phenotype as the deletions. To determine the order of these mutations, you co-infect each of them with your four deletion mutants. (+) indicates the ability to form plaques (and therefore a recombination
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Unformatted text preview: event), whereas (-) indicates that no plaques formed: a b c d e 1 - + + - - 2 + - + + + 3 + + - - - 4 + + - + + 5 - - + - - B) Draw a map that includes both the deletion and point mutations. C) Why do d and e point mutants yielded the same result? Which of the following are the possible explanations for this? Circle all the possible answer. i. They are point mutations in the same nucleotide ii. They are not in the same complementation group iii. They are point mutations in different nucleotides but they both overlap with the same deletion mutants. iv. It just happened by chance that they yielded the same result...
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This note was uploaded on 02/15/2012 for the course PMB 13 taught by Professor Freeling during the Spring '09 term at Berkeley.

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