Unformatted text preview: with probability 0.85. The children remember to feed the dog with probability 0.60. Assume independence. a) (3) Find the probability that on a given day either the parents or the children (or both) would remember to feed the dog. P( Parents OR Children ) = P( Parents ) + P( Children ) – P( Parents AND Children ) = 0.85 + 0.60 – 0.85 × 0.60 = 0.94 . OR P( Parents OR Children ) = 1 – P( nobody ) = 1 – 0.15 × 0.40 = 0.94 . b) (3) Find the probability that the dog would get fed exactly once on a given day. P( Parents only ) + P( Children only ) = 0.85 × 0.40 + 0.15 × 0.60 = 0.43 ....
View
Full Document
 Spring '08
 Kim
 Statistics, Conditional Probability, Probability, Probability theory, Bayesian probability, emergency situation, real emergency situation

Click to edit the document details