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Unformatted text preview: to arrive. P ( T 5 > 1 ) = P ( X 1 4 ) = P ( Poisson ( 3 ) 4 ) = 0.815 . OR P ( T 5 > 1 ) = ( ) 1 3 1 5 5 5 3 dt t t e = 1 3 4 5 4 3 ! dt t t e = b) (6) Find the probability that the fifth bus arrives during the third hour. P ( 2 < T 5 < 3 ) = P ( T 5 > 2 ) P ( T 5 > 3 ) = P ( X 2 4 ) P ( X 3 4 ) = P ( Poisson ( 6 ) 4 ) P ( Poisson ( 9 ) 4 ) = 0.285 0.055 = 0.230 . OR P ( 2 < T 5 < 3 ) = ( )  3 2 3 1 5 5 5 3 dt t t e = 3 2 3 4 5 4 3 ! dt t t e =...
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 Spring '08
 Kim
 Statistics, Probability

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