Unformatted text preview: probability that the seventh time the laptop needs repair will be after 3 years, when the warranty expires. P ( T 7 > 3 ) = P ( X 3 ≤ 6 ) = P ( Poisson ( 9 ) ≤ 6 ) = 0.207 . OR P ( T 7 > 3 ) = ( ) ∫ ∞ Γ3 3 1 7 7 7 3 dt t t e = ∫ ∞3 3 6 7 6 3 ! dt t t e = … b) (6) Find the probability that the seventh time the laptop needs repair will be during the second year of warranty. P ( 1 < T 7 < 2 ) = P ( T 7 > 1 ) – P ( T 7 > 2 ) = P ( X 1 ≤ 6 ) – P ( X 2 ≤ 6 ) = P ( Poisson ( 3 ) ≤ 6 ) – P ( Poisson ( 6 ) ≤ 6 ) = 0.966 – 0.606 = 0.360 . OR P ( 1 < T 7 < 2 ) = ( ) ∫Γ 2 1 3 1 7 7 7 3 dt t t e = ∫2 1 3 6 7 6 3 ! dt t t e = …...
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 Spring '05
 TBA
 Statistics, Poisson Distribution, Probability, Exponential distribution, Personal computer, Poisson process, laptop computer

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