Unformatted text preview: probability that the seventh time the laptop needs repair will be after 3 years, when the warranty expires. P ( T 7 > 3 ) = P ( X 3 ≤ 6 ) = P ( Poisson ( 9 ) ≤ 6 ) = 0.207 . OR P ( T 7 > 3 ) = ( ) ∫ ∞ Γ3 3 1 7 7 7 3 dt t t e = ∫ ∞3 3 6 7 6 3 ! dt t t e = … b) (6) Find the probability that the seventh time the laptop needs repair will be during the second year of warranty. P ( 1 < T 7 < 2 ) = P ( T 7 > 1 ) – P ( T 7 > 2 ) = P ( X 1 ≤ 6 ) – P ( X 2 ≤ 6 ) = P ( Poisson ( 3 ) ≤ 6 ) – P ( Poisson ( 6 ) ≤ 6 ) = 0.966 – 0.606 = 0.360 . OR P ( 1 < T 7 < 2 ) = ( ) ∫Γ 2 1 3 1 7 7 7 3 dt t t e = ∫2 1 3 6 7 6 3 ! dt t t e = …...
View
Full
Document
This note was uploaded on 02/15/2012 for the course STAT 400 taught by Professor Kim during the Spring '08 term at University of Illinois, Urbana Champaign.
 Spring '08
 Kim
 Statistics, Probability

Click to edit the document details