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Unformatted text preview: probability that the seventh time the laptop needs repair will be after 3 years, when the warranty expires. P ( T 7 > 3 ) = P ( X 3 ≤ 6 ) = P ( Poisson ( 6 ) ≤ 6 ) = 0.606 . OR P ( T 7 > 3 ) = ( ) ∫ ∞ Γ3 2 1 7 7 7 2 dt t t e = ∫ ∞3 2 6 7 6 2 ! dt t t e = … b) (6) Find the probability that the seventh time the laptop needs repair will be during the second year of warranty. P ( 1 < T 7 < 2 ) = P ( T 7 > 1 ) – P ( T 7 > 2 ) = P ( X 1 ≤ 6 ) – P ( X 2 ≤ 6 ) = P ( Poisson ( 2 ) ≤ 6 ) – P ( Poisson ( 4 ) ≤ 6 ) = 0.995 – 0.889 = 0.106 . OR P ( 1 < T 7 < 2 ) = ( ) ∫Γ 2 1 2 1 7 7 7 2 dt t t e = ∫2 1 2 6 7 6 2 ! dt t t e = …...
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This note was uploaded on 02/15/2012 for the course STAT 400 taught by Professor Kim during the Spring '08 term at University of Illinois, Urbana Champaign.
 Spring '08
 Kim
 Statistics, Probability

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