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Unformatted text preview: QuickTimeª and a decompressor are needed to see this picture. 10.1 Parametric Functions Parametric Functions Ch 10.1642 2 4 6642 2 4 6 In chapter 1, we talked about parametric equations. Parametric equations can be used to describe motion that is not a function. ( 29 ( 29 x f t y g t = = If f and g have derivatives at t , then the parametrized curve also has a derivative at t . → The formula for finding the slope of a parametrized curve is: dy dy dt dx dx dt = This makes sense if we think about canceling dt . The formula for finding the slope of a parametrized curve is: dy dy dt dx dx dt = We assume that the denominator is not zero. → To find the second derivative of a parametrized curve, we find the derivative of the first derivative: dy dt dx dt ′ = 2 2 d y dx ( 29 d y dx ¢ = 1. Find the first derivative ( dy/dx ). 2. Find the derivative of dy/dx with respect to t . 3. Divide by dx/dt ....
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 Fall '10
 waldron
 Derivative, dt, dx, Vectorvalued function, Δτ

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