Lab 5 Genomics - Exercise 5: Genomics Zachary Bergman...

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Exercise 5: Genomics Zachary Bergman Friday PM Section: 75 TA: Rashmi 1. I chose to compare the Caucasian group with the rest of the class. The chi-squared test gave a value of 1.7 which is less than the accepted value of a p-value of .05 which is 3.84. This means that we accept the hypothesis that distribution of genotypes among the Caucasian group occurred simply by chance. 2. By calculating only one of the three chi-squared values for both the class and the Caucasian group it is apparent that the both fail the chi-squared test because their values are greater than 3.84. This rejects the hypothesis that either group is at Hardy-Weinburg equilibrium.
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3. We observed many fewer heterozygous genotypes than expected which means that the homozygous genotype is favored in this case. The most likely conditions which explain this are mutation and non-random mating because both of these factors favor the homozygous genotype. The least likely conditions to explain this trend are genetic drift and migration
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Lab 5 Genomics - Exercise 5: Genomics Zachary Bergman...

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