Unformatted text preview: (8 points) List the concentrations of each component: 100mM acetic acid 5mM sodium acetate 5mM sodium hydroxide List the final concentrations of each ion: 10mM Acetate 10mM Sodium What is the pH of the solution? pH = pKa + log [A-] = 4.76 + log (10mM/95mM) = 4.76 – 0.98 = 3.78 [HA] 5. Two mutations (A and B) in an enzyme reduce its affinity for its substrate. Mutant A introduces a tryptophan in place of an alanine in the substrate-binding pocket. Mutant B introduces a glycine in place of a tyrosine in a distant part of the protein. Why might each of these mutations affect substrate binding? (4 points) Mutant A: Because the tryptophan is larger than alanine, it likely makes the substrate binding site less well suited to bind the substrate. Mutant B: The glycine in place of the tyrosine might create more flexibility in the protein, causing it to bind to its substrate less well....
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This note was uploaded on 02/16/2012 for the course BIOL_SCI 309 taught by Professor Somebody during the Winter '10 term at Northwestern.
- Winter '10