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problems02 - 10.16[150-887:15 For a continuous whole life...

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Unformatted text preview: 10.16. [150-887:15} For a continuous whole life insurance (Z 2 122", T a 0), 13(2) 2 0.25. Assume the forces of mortality and interest are each constant. Calculate Var(Z). (A) 0.04 (B) 0.08 (C) 0.11 (D) 0.12 (E) 0.19 10.17. [ISO-890:5] Z is the present-value random variable for a whole life insurance of l payable at the moment of death of (x). - ‘ You are given: (1) fix)»; : 0.05 fOI‘ I Z 0 (ii) a z 0.10 Which of the following are true? 1. gal). = 0 31. E[Z] : § 111. Var(Z) = é (A) I and II only (B) I and 311 only (C) 11 and HI only (D) I, H and 111 (E) The correct answer is not given by (A), (B), (C), or (D). 10.23. [150-F96:11] For a special whole life insurance on (x), you are given: (i) air) = a t 2 0 (ii) 6, = ,u, t Z 0 (iii) The death benefit, payable at the moment of death, is l for the first 10 years and 0.5 thereafter. (iv) The single benefit premium is 0.3324. (v) Z is the present—value random variable at issue of the death benefit. Caiculate Var(Z). (A) Less than 0.07 (B) At least 0.07, but less than 0.08 (C) At least 0.08, but less than 0.09 (D) At least 0.09, but less than 0.10 (E) At least 0.10 ...
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