ENC3250 Solutions pg 35

ENC3250 Solutions pg 35 - Pr [single bit not in error] = 1...

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Unformatted text preview: Pr [single bit not in error] = 1 – 10–3 = 0.999 Pr [8 bits not in error] = (1 – 10–3)8 = (0.999)8 = 0.992 Pr [at least one error in frame] = 1 – (1 – 10–3)8 = 0.008 b. Pr [at least one error in frame] = 1 – (1 – 10–3)10 = 1 – (0.999)10 = 0.01 8.3 a. b. Shift 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 0 0 0 0 1 0 0 0 1 0 0 1 1 0 0 0 0 0 0 0 1 0 0 0 1 0 0 1 1 0 0 0 0 0 0 0 1 0 0 0 1 0 0 1 1 0 0 0 0 0 0 0 1 0 0 0 1 0 0 1 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1 0 0 0 1 1 0 0 1 1 0 0 0 0 0 0 1 0 0 0 1 1 0 0 1 1 0 Shift Register 0000 0000 0001 0010 0100 1000 0001 0011 0110 1100 1001 0011 0110 1101 1011 0111 1110 CRC -35- Input 0 1 0 0 0 1 1 0 0 1 1 0 1 1 1 0 0 0 0 0 0 0 1 0 0 0 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 1 0 0 0 1 0 0 1 1 0 0 0 1 0 0 0 1 0 0 0 1 0 0 1 1 0 0 0 1 0 0 0 1 0 0 0 1 0 0 1 1 0 0 0 1 0 0 0 1 0 0 0 1 0 0 1 1 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ...
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This note was uploaded on 02/20/2012 for the course ENC 3250 taught by Professor Dr.timothycerner during the Fall '11 term at UNF.

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