ENC3250 Solutions pg 51

ENC3250 Solutions - -51-For N= 12 kCE= 55 channelsFor N= 19 kCE= 35 channelsc.For N= 4 area = 64 cells For N= 7 area = 112 cells For N= 12 area =

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: -51-For N= 12, kCE= 55 channelsFor N= 19, kCE= 35 channelsc.For N= 4, area = 64 cells; For N= 7, area = 112 cells; For N= 12, area = 192 cells;For N= 19, area = 304 cells.d.From part b, we know the number of channels that can be carried per cell foreach system. The total number of channels available is just 100 times thatnumber, for a result of 16600, 9500, 5500, 3500, respectively. Source: [CARN99]10.2 a.Steps a and b are the same. The next step is placing the call over the ordinarypublic switched telephone network (PSTN) to the called subscriber. Steps d, e,and f are the same except that only the mobile unit can be involved in ahandoff.b.Instead of steps a, b, and c, the process starts with a call coming in from thePSTN to an MTSO. From there, steps c, d, e, and f are the same except that onlythe mobile unit can be involved in a handoff.10.3This causes additional interference to co-channel users....
View Full Document

This note was uploaded on 02/20/2012 for the course ENC 3250 taught by Professor Dr.timothycerner during the Fall '11 term at UNF.

Ask a homework question - tutors are online