63
a2.
One 16PPM symbol represents 4 bits. Therefore, the period for symbol
transmission is 4 μs. There is one pulse in each symbol, so the average time
between pulses is 4 μs.
a3.
Each symbol consists of 16 pulse positions, with only one pulse present. If the
adjacent symbols are 0000000000000001 and 1000000000000000, then the time
between pulses is 4/16 = 0.25 μs.
a4.
If the adjacent symbols are 1000000000000000 and 0000000000000001, then the
time between pulses is 31
×
0.25 = 7.75 μs
b1.
The 4PPM scheme is for the 2Mbps data rate. Therefore, the period for bit
transmission is 1/(2
×
10
6
) = 0.5 μs.
b2.
One 4PPM symbol represents 2 bits. Therefore, the period for symbol
transmission is 1 μs. There is one pulse in each symbol, so the average time
between pulses is 1 μs.
b3.
Each symbol consists of 4 pulse positions, with only one pulse present. If the
adjacent symbols are 0001 and 1000, then the time between pulses is 1/4 = 0.25
μs.
b4.
If the adjacent symbols are 1000 0001, then the time between pulses is 7
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 Fall '11
 Dr.TimothyCerner
 4 bits, 2 bits, two bits, one bit, subcarriers

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